Time Limit: 1000MS Memory Limit: 30000K
Total Submissions: 4863 Accepted: 1058 DescriptionWhen a thin rod of length L is heated n degrees, it expands to a new length L'=(1+n*C)*L, where C is the coefficient of heat expansion. When a thin rod is mounted on two solid walls and then heated, it expands and takes the shape of a circular segment, the original rod being the chord of the segment.Your task is to compute the distance by which the center of the rod is displaced.
Input
The input contains multiple lines. Each line of input contains three non-negative numbers: the initial lenth of the rod in millimeters, the temperature change in degrees and the coefficient of heat expansion of the material. Input data guarantee that no rod expands by more than one half of its original length. The last line of input contains three negative numbers and it should not be processed.
OutputFor each line of input, output one line with the displacement of the center of the rod in millimeters with 3 digits of precision.
Sample Input
1000 100 0.000115000 10 0.0000610 0 0.001-1 -1 -1
Sample Output61.329
225.0200.000
SourceWaterloo local 2004.06.12
// POJ1905.cpp : Defines the entry point for the console application. // #include < iostream > #include < cmath > #include < algorithm > using namespace std; int main( int argc, char * argv[]){ double N,C,L; while (scanf( " %lf%lf%lf " , & L, & N, & C) && N >= 0 && C >= 0 && L >= 0 ) { if (N == 0 || L == 0 || C == 0 ) { printf( " 0.000\n " ); continue ; } double minv = 0 ,maxv = acos( - 1.0 ), midv; double L2 = ( 1 + N * C ) * L; while (maxv - minv > 1e - 12 ) { midv = (minv + maxv) / 2 ; if ( 2 * L2 / L > midv / sin(midv / 2 )) minv = midv; else maxv = midv; } printf( " %.3lf\n " ,L2 / midv * ( 1 - cos(midv / 2 ))); } return 0 ;}